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8.2t^2+1341t-40000=0
a = 8.2; b = 1341; c = -40000;
Δ = b2-4ac
Δ = 13412-4·8.2·(-40000)
Δ = 3110281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1341)-\sqrt{3110281}}{2*8.2}=\frac{-1341-\sqrt{3110281}}{16.4} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1341)+\sqrt{3110281}}{2*8.2}=\frac{-1341+\sqrt{3110281}}{16.4} $
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